How to find minimum possible mass

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Homework Help Overview

The discussion revolves around determining the minimum possible mass in a collision scenario involving an unknown mass and a known mass of 2 kg. The context includes concepts of impulse, momentum change, and the relationship between velocities post-collision.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of impulse and momentum to relate the unknown mass's velocity to that of the known mass. Questions arise about the necessity of certain variables and the implications of finding a minimum mass.

Discussion Status

There is an ongoing exploration of the relationships between the variables involved, with some participants suggesting the need to consider energy and the final velocities of the objects. No consensus has been reached, but various lines of reasoning are being examined.

Contextual Notes

Participants express uncertainty about how to apply the concept of minimum mass and the relevance of specific velocities in the problem setup.

ssarpal
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Homework Statement
A block of mass m moving at a speed 4 m/s collides with a block of mass 2 Kg initially at rest. The force during collision varies as the function F = A*sin^2(Bt). The collision lasts for 1 ms.

Find the minimum possible mass m?
##A = 10^4 N##

##B = 1000\pi \hspace{2mm} rad/sec##
Relevant Equations
Change in momentum is equal to the integral of force with respect to time.
lagrida_latex_editor (2).png

Unfortunately, this is not the right answer.
 
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The integral gives you the impulse ##J## which is the momentum change of the unknown mass. After the collision, this mass will still be moving with velocity ##v_1## and the 2 kg will also be moving with velocity ##v_2## because it received impulse ##J## in the opposite direction. Do you see how to tie all this together?
 
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ssarpal said:
this is not the right answer.
Did it bother you that you were asked to find a minimum, but you did not go through such a step?
 
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kuruman said:
The integral gives you the impulse ##J## which is the momentum change of the unknown mass. After the collision, this mass will still be moving with velocity ##v_1## and the 2 kg will also be moving with velocity ##v_2## because it received impulse ##J## in the opposite direction. Do you see how to tie all this together?
I think that means
##mu_1 = mv_1 +m_2v_2##
where ##u_1## = 4 m/s and ##m_2## = 2 Kg
Am not sure if ##v_1## and ##v_2## are needed to solve this?
 
haruspex said:
Did it bother you that you were asked to find a minimum, but you did not go through such a step?
Yes, was wondering where it could be used, am not sure how though.
 
ssarpal said:
Yes, was wondering where it could be used, am not sure how though.
Perhaps you need to think about energy?
 
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The first thing to ask oneself is: What are the possible final velocities of each object and what is the mass m for each of those velocities?
 
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