How to find the angle between wire and magnetic field

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SUMMARY

The discussion focuses on calculating the angle between a current-carrying wire and a magnetic field using the formula F = BILsin(θ). Given a wire length of 0.655 m, a current of 21.0 A, and a magnetic field strength of 0.470 T, the force experienced by the wire is 5.46 N. The calculation leads to sin(θ) = 0.844567, indicating that θ can be determined using the inverse sine function.

PREREQUISITES
  • Understanding of the formula F = BILsin(θ)
  • Knowledge of magnetic fields and forces on current-carrying conductors
  • Familiarity with inverse trigonometric functions
  • Basic algebra for manipulating equations
NEXT STEPS
  • Learn how to apply inverse sine functions to find angles
  • Study the principles of electromagnetism related to forces on wires
  • Explore the implications of varying magnetic field strengths on wire forces
  • Investigate real-world applications of current-carrying wires in magnetic fields
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Students in physics, educators teaching electromagnetism, and anyone interested in the practical applications of magnetic fields and electric currents.

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Homework Statement



A wire of length 0.655 m carries a current of 21.0 A. In the presence of a 0.470-T
magnetic field, the wire experiences a force of 5.46 N. What is the angle (less than
90degrees) between the wire and the magnetic field?


Homework Equations



Is there a special formula to solve this equation?
If what I have done below is correct, how do I find Theta if all I know is
the sin of Theta?

The Attempt at a Solution


I used the equation F=BILsinTheta
5.46=.655m*21.0A*.470T*sinTheta
5.46=6.46485*sinTheta
5.46/6.46485=sinTheta
.844567 = sinTheta
 
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Err... How far along are you in math? Have you ever encountered inverse trig functions?
 

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