- #1

- 581

- 20

## Homework Statement

## Homework Equations

d(y)/d(x) --> max area

area of triangle = 1/2 . base . height

## The Attempt at a Solution

for number (2) [/B]

x^2 + y^2 = r^2 --> circle equation

base = 2R, height = y

Area = 1/2 . 2R . y

area = 1/2 . 4. √ (r^2 - x^2)

area now is half of max = 2, so :

2 = 1/2 . 4. √ (r^2 - x^2)

2 = 2 √(4-x^2)

1 = √ (4-x^2)

1 = 4 - x^2

x = √3

now y = 1

AP = 2 - √3

I have to find w (angle of ACB)

PC = 1

how to find w ?