How to find the Dielectric Strength

Click For Summary

Homework Help Overview

The discussion revolves around determining the dielectric strength of a capacitor, specifically one with square plates measuring 90mm by 90mm and a dielectric thickness of 0.29mm, rated for 300V. The original poster expresses uncertainty about how to approach the problem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula for capacitance and the parameters involved, such as dielectric thickness and area. There are inquiries about the original problem's source and its relevance to exam preparation.

Discussion Status

Some participants have provided calculations related to capacitance, while others are seeking clarification on how to proceed further. There is an exchange of information regarding the problem's context and its appearance in exams, indicating a collaborative effort to understand the topic.

Contextual Notes

Participants note the specific parameters of the capacitor and the voltage rating, which may influence the calculation of dielectric strength. There is a mention of previous exam experiences, suggesting a shared concern about understanding similar problems in the future.

jra_1574
Messages
12
Reaction score
0
Hello, everyone!

I have a question, and i don't know how to solve it...
They ask me for the dielectric strength!
How do i find it?
 
Physics news on Phys.org
Type out the entire problem so we can help you...
 
The full question is like this:

The square plates of a 9000pF capacitor measure 90mm by 90mm and are separated by a dielectric which is 0.29mm thick. The voltage rating of the capacitor is 300V. THe dielectric strength, in KV/m is closest to:
A. 1300
B. 930
C. 1200
D. 1100
E. 1000

To be honest i have no idea how to approach this problem.
 
for such a capacitor,the capicitance is given by

[tex]C=\frac{\epsilon_0 A}{d}[/tex] where d=thickness and A=area
 
ok i did the calculation

Eo = 8.85 x10^-12
A= 8.1x10^-3
d = 2.9x10^-4


so the final answer is C = 2.4719x10^-10

Now what should i do?
 
Can u tell me where did u find the problem coz that was the same question in my exam? So that I can predict future exam qts.
 
It was actually in my exam a few years ago.. i solved the problem in class tho... i don't remember the answer, but the equation given here was very useful... :)
 

Similar threads

Replies
6
Views
3K
Replies
14
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
2K
Replies
3
Views
2K
Replies
2
Views
1K