Find the dielectric constant of the medium?

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SUMMARY

The dielectric constant (ϵr) of a medium can be calculated by comparing the electrostatic forces exerted by two point charges in free space and in a dielectric medium. In this case, the force in free space is 1.4×10^−4 N, while in the dielectric medium it is 0.9×10^−4 N. The relationship between these forces and the dielectric constant is given by the formula ϵr = F_free_space / F_medium. Therefore, the dielectric constant is 1.4 / 0.9, which equals approximately 1.56.

PREREQUISITES
  • Understanding of Coulomb's Law and electrostatic force calculations
  • Familiarity with the concept of dielectric materials
  • Basic knowledge of electric field equations, specifically E=F/Q
  • Ability to manipulate ratios and perform basic algebraic calculations
NEXT STEPS
  • Study the properties and applications of dielectric materials in physics
  • Learn about the derivation and implications of Coulomb's Law
  • Explore the concept of electric fields in different media
  • Investigate how dielectric constants affect capacitance in capacitors
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This discussion is beneficial for physics students, educators, and anyone interested in understanding electrostatics and the behavior of materials in electric fields.

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Homework Statement


Two point charges a distance d apart in free space exert a force of 1.4∗10^−4 [N]. When the free space is replaced by a homogeneous dielectric medium, the force become .9∗10^−4 [N]. What is the dielectric constant ϵr of the medium?


Homework Equations


E=F/Q


The Attempt at a Solution


I have been staring at this problem for awhile. I can only think of using E=F/Q. But the problem is this only applies to free space and I do not know Q. So I am not sure where to start to compare the free space and medium.
 
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The coulombic force in free space is k.q1.q2/r^2. In a medium, the value of k changes to k/dielectric constant. Now try to solve the question. :D
Hint : Compare the 2 values of electrostatic force.
 

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