How to Find the Electric Field on the XY-Plane from a Line Charge?

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SUMMARY

The discussion focuses on calculating the electric field at points on the XY-plane due to a line charge extending from -L to L along the Z-axis. The relevant equations include the electric field formula, \(E(r)=k\int\frac{\rho}{r^2}dq\), where \(k=\frac{1}{4\pi ε_o}\) and \(dq=\lambda dz\). The integral for the electric field is derived as \(E(x, y, 0) = k \int_{-L}^L \frac{\lambda}{z^2+x^2+y^2}dz\). The participants emphasize the importance of correctly identifying the geometry of the problem to accurately compute the contributions from the line charge.

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Homework Statement


A wire at extends for -L to L on the z-axis with charge ##\lambda##. Find the field at points on the xy-plane


Homework Equations



##E(r)=k\int\frac{\rho}{r^2}dq##
##k=\frac{1}{4\pi ε_o}##

The Attempt at a Solution



First time I've looked for field on a plane so I wasn't sure if I'm doing this correctly.

##dq=\lambda dz=2L\lambda##
I made a right triangle with one side L and the other two x and y.
##r^2=L^2+x^2+y^2## where only x and y change so I have dxdy.

So, the final integral

##k(2L\lambda)\int\int\frac{1}{L^2+x^2+y^2}dxdy## with limits 0→∞.

I expect at large x,y that the field should be very small and small x,y it should be large. This integral satisfies both of those conditions.

The method I saw our professor do for another, somewhat similar, problem was exceedingly more complicated than this.
 
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Hmm, the question is to find the field at some point (x, y, 0). So you should fix x and y, and add up all the contributions from the charges on the z-axis.
Therefore I would expect something like
$$E(x, y, 0) = k \int_{-L}^L \frac{\rho}{r^2} \, dz$$
(where did your ##\rho## go? Should there not be something with ##\lambda## in there)?

Try drawing such a point, and calculating ##r## and ##\rho \, dz## from the geometry of the problem rather than by trying to copy your notes.
 
##\rho## is the charge density ##\lambda##
I was trying to use ##\rho## in the general sense but I sort of got ahead of myself putting it in there.

##E(r)=k\int\frac{1}{r^2}dq##

##dq=\lambda dz##

so, ##E(r)=k\int\frac{\lambda}{r^2}dz##


As soon as I walked away from the computer I knew I was wrong. My whole way of thinking was stuck in previous problems I've done.

X and Y are my points of interest and Z is my variable (for the line charge not on the plane). So if I want to figure out what the field is at X and Y I need to count up all the little pieces of charge at distance 'r' from them to the line.

I have ##\int_{-L}^{L} \frac{\lambda}{z^2+x^2+y^2}dz##
 

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