- #1

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- Homework Statement:
- a problem in Graphing electric field lines

- Relevant Equations:
- dy/dx = Ey/Ex

hi guys

our instructor asked us to try to graph the projection of the electric field intensity at a certain point p(x,y) , for two charges q+-q located

at (-a,0) , (a,0), Now starting with the equation

$$\frac{dy}{dx} = \frac{E_{y}}{E_{x}}$$

after transforming this equation I got

$$\frac{du}{(1+u^{2})^{3/2}}=\frac{dv}{(1+v^{2})^{3/2}}$$

where $u = (x+a)/y$ , $v = (x-a)/y$

my question is how would I plot the solution of this equation to get the graph of the electric field?

our instructor asked us to try to graph the projection of the electric field intensity at a certain point p(x,y) , for two charges q+-q located

at (-a,0) , (a,0), Now starting with the equation

$$\frac{dy}{dx} = \frac{E_{y}}{E_{x}}$$

after transforming this equation I got

$$\frac{du}{(1+u^{2})^{3/2}}=\frac{dv}{(1+v^{2})^{3/2}}$$

where $u = (x+a)/y$ , $v = (x-a)/y$

my question is how would I plot the solution of this equation to get the graph of the electric field?