Equation of a plane perpendicular to another plane

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Homework Help Overview

The original poster seeks to find the equation of a plane that is perpendicular to another plane defined by the equation 5x + 4y - 3z = 8, and that passes through a specific line represented by the relationship x = 2y = 3z. The problem involves concepts from analytic geometry, particularly the relationships between planes and lines in three-dimensional space.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the need to identify a line or vector that is perpendicular to the given plane, with some suggesting that this involves finding a normal vector. Questions arise about how to determine this normal vector and its relationship to the planes involved.

Discussion Status

The discussion is ongoing, with some participants providing guidance on the concepts of normal vectors and the equations of lines and planes. However, there is a lack of explicit consensus on the methods to be used, and the original poster expresses uncertainty about how to proceed.

Contextual Notes

There is mention of the original poster not having made much effort in their inquiry, which is noted as a requirement for homework posts. Additionally, references to external resources such as textbooks and Wikipedia articles are made, indicating a need for further exploration of the topic.

Josie Jones
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Hi, I am really stuck! I need to find the equation of the plane through the line x=2y=3z perpendicular to the plan 5x+4y-3z=8. Can anyone give me any pointers of where to start with this? Not expecting a full solution, just an idea of where to start.

THanks!
 
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I moved this thread to our homework section. Can you find a line (or just a vector) that is perpendicular to the second plane? What do you know about that line (or vector) relative to one of the planes you are looking for?
 
mfb, thanks for moving the thread.

I don't know how to find a perpendicular line or vector. I think it is a normal vector, but I have not been shown how to do this. I found this question in a book and am unsure how to proceed.

thanks for your reply
 
Josie Jones said:
Hi, I am really stuck! I need to find the equation of the plane through the line x=2y=3z perpendicular to the plan 5x+4y-3z=8.

Josie Jones said:
I don't know how to find a perpendicular line or vector. I think it is a normal vector, but I have not been shown how to do this. I found this question in a book and am unsure how to proceed.
If the book was a textbook on analytic geometry it should have sections on the equations of lines and planes in space, and how to determine the orientation of these objects.

Given the equation of a plane in standard form, Ax + By + Cz = D, it is very simple to find a normal to the plane. It's also straightforward to find a vector in the direction of a line.

Since you haven't made much of an effort, which is required for homework posts, I am closing this thread. Please go back and do some digging in your book. Another resource is this wikipedia article on planes -- https://en.wikipedia.org/wiki/Plane_(geometry). I'm sure they also have an article on lines in space.
 
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