How to find the FWHM-diameter of the SH beam?

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SUMMARY

The discussion focuses on calculating the Full Width at Half Maximum (FWHM) diameter of a second harmonic (SH) beam generated from a Gaussian laser beam with a wavelength of 1064 nm and an initial FWHM-diameter of 5 mm. The SH beam radiates at a wavelength of 532 nm and co-propagates with the fundamental beam. The relationship between the FWHM of the incoming beam and the SH beam is established through the equation dFWHM = ω(z)√2ln2, which requires understanding the propagation characteristics of the beam in nonlinear optics.

PREREQUISITES
  • Understanding of Gaussian beam propagation
  • Knowledge of nonlinear optics principles
  • Familiarity with the concept of Full Width at Half Maximum (FWHM)
  • Basic proficiency in mathematical manipulation of optical equations
NEXT STEPS
  • Study Gaussian beam propagation and its parameters
  • Research nonlinear optical processes and their effects on beam characteristics
  • Learn about the mathematical derivation of FWHM in different contexts
  • Explore the implications of frequency doubling in laser systems
USEFUL FOR

Optical engineers, physicists, and students studying laser technology and nonlinear optics will benefit from this discussion, particularly those interested in beam propagation and frequency conversion processes.

telekom90
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Homework Statement


Assume a Gaussian laser beam ( 1064 nm wavelength) having an FWHM-diameter(intensity) of 5 mm. By transmission through a thin nonlinear crystal, a new wave is generated that is proportional to the square of the incoming field (and therefore radiates at twice the frequency, or 532nm wavelength). This second harmonic (SH) beam co-propagates with the fundamental laser beam. What is the FWHM-diameter of the SH beam?

Homework Equations



dFWHM = ω(z)√2ln2

The Attempt at a Solution


λ =1064nm, dFWHM=5 mm##, ## λSH=532 nm .
I can't solve this problem because I don't know how to relate this equation "dFWHM=ω(z)√2ln2= 5mm " with the FWHM-diameter of second harmonic (SH) beam?!
 
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The key word is
telekom90 said:
that is proportional to the square of the incoming field
.
 

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