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How to find the FWHM-diameter of the SH beam?

  1. Nov 7, 2016 #1
    1. The problem statement, all variables and given/known data
    Assume a Gaussian laser beam ( 1064 nm wavelength) having an FWHM-diameter(intensity) of 5 mm. By transmission through a thin nonlinear crystal, a new wave is generated that is proportional to the square of the incoming field (and therefore radiates at twice the frequency, or 532nm wavelength). This second harmonic (SH) beam co-propagates with the fundamental laser beam. What is the FWHM-diameter of the SH beam?

    2. Relevant equations

    dFWHM = ω(z)√2ln2

    3. The attempt at a solution
    λ =1064nm, dFWHM=5 mm##, ## λSH=532 nm .
    I can't solve this problem because I don't know how to relate this equation "dFWHM=ω(z)√2ln2= 5mm " with the FWHM-diameter of second harmonic (SH) beam?!
     
  2. jcsd
  3. Nov 11, 2016 #2

    blue_leaf77

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    The key word is
    .
     
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