- #1

- 366

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## Homework Statement

Find the integrated rate law for a first order reaction

## The Attempt at a Solution

We have r = -d[A]/dt = k[A]

Integration with respect to [A] gives

[A] = (1/2)k*[A]^2

Is this it?

- Thread starter kasse
- Start date

- #1

- 366

- 0

Find the integrated rate law for a first order reaction

We have r = -d[A]/dt = k[A]

Integration with respect to [A] gives

[A] = (1/2)k*[A]^2

Is this it?

- #2

- 378

- 2

1/(k*[A]) . d[A] = dt

1/(k*[A]) . d[A] = t

now integrate left side ..

I am pretty sure that you have got it wrong

- #3

- 366

- 0

ln[A] + [A]_{0} = kt

Is this the correct form?

Is this the correct form?

Last edited:

- #4

- 366

- 0

ln[A] + C = kt

Can anyone explain why the integration constant is ln[A]_{0}?

Can anyone explain why the integration constant is ln[A]

- #5

- 378

- 2

that's due to the integration limits

{from 0 to t}

ln(A) is at t and ln[A]0 is 0

{from 0 to t}

ln(A) is at t and ln[A]0 is 0

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