The simplest way to determine the radius of convergence is to use the "ratio test".
[tex]a_n= \frac{(-1)^{n-1}(x- 2)^{n-1}}{5^n}[/tex]
[tex]a_{n+1}= \frac{(-1)^n(x- 2)^n}{5^{n+1}}[/tex]
What is [itex]\left|\frac{a_{n+1}}{a_n}\right|[/itex]? What is the limit of that as n goes to infinity? For what x is that limit less than 1?