How to find the normal force given the center of gravity and the radius

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SUMMARY

The discussion focuses on calculating the normal force exerted by each hand and foot of a person performing pushups, given a total weight of 584 N and specific distances from the center of gravity. The center of gravity is located at the waist, with distances of 0.410 m from the waist to the hands and 0.840 m from the waist to the feet. The solution involves analyzing torques around the fulcrum, which is the waist, and applying the principles of static equilibrium to determine the forces acting on the hands and feet.

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Pinkchika88
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Homework Statement


a person is doing pushups and its weight is 584 N, center of gravity is at waist and from waist to hands=.410m and from waist to feet=.840m. find the normal force on each hand and each foot


Homework Equations





The Attempt at a Solution


do u have to find the weight on top half of body and then weight on lower half (the force being applied by the hands/feet)?
 
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Pinkchika88 said:

Homework Statement


a person is doing pushups and its weight is 584 N, center of gravity is at waist and from waist to hands=.410m and from waist to feet=.840m. find the normal force on each hand and each foot
This is a torque problem. Analyse the torques about the fulcrum. Where is the fulcrum? What kind of a lever is this? Find the normal force at the top (or bottom) of a push- up - ie. ignore any angular acceleration. Also, assume there are no differences between left and right hands and between left and right feet.

AM
 

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