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How to find the positon of a local vector

  1. Oct 27, 2015 #1
    1. The problem statement, all variables and given/known data
    Determine the resultant force R that is equvalent to the forces exerted by the tugboats on the barge. Specify the coordinates of the point on the x axis through which R passes.
    Pls check attached file!

    2. Relevant equations
    Moment=Force x perpendicular distance

    3. The attempt at a solution
    Findin the R resulted to 15.7i + 11j
    Total moment about A gives 8tons.m clockwise.
    Then using this force-couple system, the resultant force should be placed such that it yields the same moment.
    Letting x be the distance between Ry(y component so I get a perpendicular relationship) and pt. A, and equating the moment(that of R and the 8tons.m) reveals that x=0.7m. Then the coord is 60m-.7m=59.3m.
     

    Attached Files:

  2. jcsd
  3. Oct 28, 2015 #2

    haruspex

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    You forgot something.
     
  4. Oct 28, 2015 #3
    Dont see anything. What did I miss?
     
  5. Oct 28, 2015 #4

    haruspex

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    The force is 8 tons. What is the moment from the force about A?
     
  6. Oct 31, 2015 #5
    Oh..60x8tons.m
     
  7. Oct 31, 2015 #6
    So...55.6m?
     
  8. Oct 31, 2015 #7

    haruspex

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    As x coordinate? Seems much too large. Please post your revised working.
     
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