How to find the positon of a local vector

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SUMMARY

The discussion focuses on determining the resultant force R exerted by tugboats on a barge and its position along the x-axis. The resultant force is calculated as 15.7i + 11j, with a total moment about point A measured at 8 tons·m clockwise. The distance x, which relates to the y-component of the resultant force, is found to be 0.7m, leading to a coordinate of 59.3m on the x-axis. Participants emphasize the importance of correctly calculating the moment from the force to ensure accurate positioning.

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Homework Statement


Determine the resultant force R that is equvalent to the forces exerted by the tugboats on the barge. Specify the coordinates of the point on the x-axis through which R passes.
Pls check attached file!

Homework Equations


Moment=Force x perpendicular distance

The Attempt at a Solution


Findin the R resulted to 15.7i + 11j
Total moment about A gives 8tons.m clockwise.
Then using this force-couple system, the resultant force should be placed such that it yields the same moment.
Letting x be the distance between Ry(y component so I get a perpendicular relationship) and pt. A, and equating the moment(that of R and the 8tons.m) reveals that x=0.7m. Then the coord is 60m-.7m=59.3m.
 

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Aceix said:
Total moment about A gives 8tons.m clockwise.
You forgot something.
 
haruspex said:
You forgot something.
Dont see anything. What did I miss?
 
Aceix said:
Dont see anything. What did I miss?
The force is 8 tons. What is the moment from the force about A?
 
haruspex said:
The force is 8 tons. What is the moment from the force about A?
Oh..60x8tons.m
 
So...55.6m?
 
Aceix said:
So...55.6m?
As x coordinate? Seems much too large. Please post your revised working.
 

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