How To Find The Sin(A+B)=SinA.CosB+CosA.SinB?

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optics.tech
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Hi everyone,

I wonder why Sin(A+B)=SinA.CosB+CosA.SinB?

Huygen
 
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The easiest way to see this is to use Euler's formula:
[tex]e^{ix} = cos(x) + i sin(x)[/tex]

put in A+B for x, expand it, and collect real and imaginary parts.