How to find the weight of an object given the force

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SUMMARY

The weight of the wooden door is determined by the force required to lift it, which is 400N. Using the formula F=ma, where acceleration is approximated as 10m/s², the mass of the door calculates to 40kg, resulting in a weight of 400N. To accurately analyze the forces, it is essential to consider torque equilibrium about the hinge and identify the center of gravity (CG) of the door. A free body diagram (FBD) is recommended for visualizing the forces acting on the door.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Basic knowledge of torque and equilibrium
  • Ability to draw and interpret free body diagrams (FBD)
  • Familiarity with concepts of center of gravity (CG)
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  • Learn how to calculate torque in static equilibrium scenarios
  • Study the principles of free body diagrams (FBD) in physics
  • Explore the concept of center of gravity (CG) in various shapes
  • Investigate real-world applications of force and weight calculations
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Homework Statement


An old, heavy wooden door leads to a basement storm cellar. If it requires 400N to lift the door by its handle and swing it open, what is the Weight (in N) of the door itself? (Also, there is a picture that shows from the hinge to the handle is 1.6m)

Homework Equations


F=ma ?

The Attempt at a Solution


I usually get stuck on the easiest of problems because I over think them. Would I just use the F=ma formula? Plugging it in as: 400N=m(10m/s)? (My teacher allows us to use 10 instead of 9.8 for acceleration). If so, the mass would come out to be 40kg which in turn is 400N.

I would appreciate the help if I did this wrong. Thanks!
 
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Are you familiar with momentum?
 
mishek said:
Are you familiar with momentum?

My mistake, acceleration is m/s^2. It's velocity that is just m/s which is included in calculating momentum.. P=mv. Do I use this formula somehow?
 
You should consider taking moments of forces about the hinge and assume that the door is initially raised very slowly and is in equilibrium ( not accelerating) during the initial force application. First identify the forces acting on the door before applying the torque equilibrium equation.
 
PhanthomJay is right. It would help to draw a free body diagram. You will also have to either know where the CG of the door is, or assume it to be in the center of the door. If that be so, the weight will work out to twice that required to open it. (Drawing the FBD and working the equations in my head. You might want to check me by doing it on paper.)
 

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