How to find values of a variable of a plane

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SUMMARY

The discussion centers on solving a system of equations represented by three planes: (3-a)x - 2y - 4z = 0, -2x - (2+a)y + 6z = 0, and 4x + 6y - (1+a)z = 0. The user attempted to expand the equations and apply the elimination method but struggled to find a value for the variable "a" that allows for nontrivial solutions. It was concluded that knowledge of Linear Algebra is essential for tackling this problem effectively, as precalculus methods may not suffice.

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Homework Statement



I am given 3 planes

1) (3-a)x-2y-4z=0
2)-2x-(2+a)y+6z=0
3) 4x+6y-(1+a)z=0

The Attempt at a Solution



So what i did was i expanded the equation

1) 3x-xa-2y-4z=0
2)-2x-27-ya+6z=0
3)4x+6y-z+az=0

and i used the elimination method using

3x-xa-2y-4z=0
-2x-27-ya+6z=0

what i got was a= -10y+10z / 2x-3y

Now i do not know what to do next, i do not even know if i am doing this right can someone help
Thanks!
 
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What are you trying to do? I think you are trying to find a value of "a" for which there are nontrivial solutions to this system of equations. This is a very difficult question that you have asked, infeasable I think with precalculus math.

I'll look at it some more though.

Hmm, unless you know Linear Algebra, give this one a miss.
 
Last edited:

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