How to Find Velocity-Time Graph from Position-Time Graph?

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To find a velocity-time graph from a position-time graph, one must determine the slope of the curve at each point. This slope represents the change in position over the change in time, which corresponds to velocity. While differentiation is a common method, it is not necessary; instead, one can estimate the slope by calculating the change in y (position) over the change in x (time) for small intervals. This approach allows for the extraction of velocity values without formal differentiation. Understanding this concept is key to accurately representing motion in a velocity-time graph.
teetar
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Homework Statement


Not too necessary to follow this format, but here is my question: I know I probably shouldn't ask such a simple question, but how do I find a velocity-time graph from a position-time graph? I know it's just slope, but I'm looking at a curve, and I don't want to differentiate it. I also know that this is probably not as difficult as I'm making it, but I'm completely blanking on this one. Any help will be greatly appreciated. Thanks guys!

Homework Equations


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The Attempt at a Solution


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teetar said:

Homework Statement


Not too necessary to follow this format, but here is my question: I know I probably shouldn't ask such a simple question, but how do I find a velocity-time graph from a position-time graph? I know it's just slope, but I'm looking at a curve, and I don't want to differentiate it. I also know that this is probably not as difficult as I'm making it, but I'm completely blanking on this one. Any help will be greatly appreciated. Thanks guys!

Homework Equations


N/A

The Attempt at a Solution


N/A

You are right that it is the slope at each point, so just look at delta-y / delta-x at each point.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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