How to get equation for velocity of Pendulum

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SUMMARY

The discussion focuses on deriving the equation for the velocity of a pendulum using the formula for period T = 2π√(L/g). The user attempted to combine centripetal acceleration (a = 1/2 V²/r) with gravitational acceleration (a = g(sinθ)) to arrive at the velocity equation v = √(2gL(sinθ)). However, there is uncertainty regarding the validity of this approach due to the differing nature of the accelerations involved. A suggestion is made to start with the equation of motion θ = θ₀*cos(2πt/T) for a more accurate derivation.

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Homework Statement





Homework Equations



T=2pi(sq.root L/g)

The Attempt at a Solution

combined a=1/2 V^2/r with a=g(sinO) then solved for v.
got v=Sq.root 2gL(sinO). Don't know if this is right.
 
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I doubt if that approach works - the one acceleration is vertical while the other is radial.

I suggest beginning with the equation of motion
θ = θo*cos(2πt/T)
 

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