How to get position operator in momentum space?

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To obtain the position operator in momentum space using Fourier transformation, start by expressing the wave function Ψ(x) in terms of its Fourier transform, Ψ(p). The relationship between a function and its Fourier transform allows for the manipulation of derivatives, as seen in the transformation of f'(x) to its momentum space equivalent. The discussion emphasizes the need to show work for clarity and constructive feedback. Additionally, there is a consideration of whether to use wave functions or Dirac notation in the derivation process.
azoroth134
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Hi, I wish to get position operator in momentum space using Fourier transformation, if I simply start from here,

$$ <x>=\int_{-\infty}^{\infty} dx \Psi^* x \Psi $$

I could do the same with the momentum operator, because I had a derivative acting on |psi there, but in this case, How may I get the ih d/dp thing for the position operator, please give some hint
 
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Well, since you only wanted a hint...

Express ##\Psi(x)## in terms of its Fourier transform ##\tilde\Psi(p)## .
 
I already did that, I just don't know what to do after that, I don't have any derivative to perform on x or p
 
For a function ##f(x)## and its Fourier transform ##F(k)## (assuming it has one), we have the relation ##f'(x) = FT[ikF(k)]## and the inverse transform ##ikF(k) = FT^{-1}[f'(x)]##. Using this how would you write ##x\psi(x)## in momentum space?
 
azoroth134 said:
I already did that [...]
Heh, then you should show your work. (Asking only vague questions makes it harder for others to help you constructively.)
 
...and do you have to do it with wave functions, or is Dirac notation allowed?
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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