How to get the equation of the plane. [read this one]

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SUMMARY

The equation of the plane can be derived from its vertices using the standard form ax + by + cz = 0. By substituting the points (1,1,0) and (0,1,1) into the equation, it is established that a = -b and b = -c. This leads to the simplified equation x - y + z = 0, confirming the relationship between the coefficients and the vertices provided.

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http://www.isquaredonline.com/chips/1.jpg

the above link is the answer to the problem I'm solving. i was wondering how i'd come up with the equation of the plane "x-y+z=0" when only the vertices of the plane are provided in the problem. thanks in advance.
 
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The equation of a plane through the origin is always of the form ax+by+cz=0.
Now you can plug in some points. Say, put in (1,1,0) and you'll find a=-b.
Putting in (0,1,1) b=-c. So the equation reduces to ax-ay+az=0 or x-y+z=0.
 
thanks for the help.
 

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