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How to go from 2*4*6 (2n) to (2^n)n!

  1. Oct 25, 2013 #1
    how would one see the first

    and come up with the second
     
  2. jcsd
  3. Oct 25, 2013 #2

    SteamKing

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    Have you tried factoring 2 from 2*4*6*...(2n)?
     
  4. Oct 25, 2013 #3

    Mark44

    Staff: Mentor

    In the product 2 * 4 * 6 * ... * (2n), how many factors are explicitly shown there?
     
  5. Oct 25, 2013 #4

    vanhees71

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    I write it even a bit more explicitly
    [tex]2 \cdot 4 \cdot 6 \cdots (2n)=(2 \cdot 1) \cdot (2 \cdot 2) \cdot (2 \cdot 3) \cdots (2n).[/tex]
     
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