Sep 24, 2003 #2 HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 984 Use " ^ (1/3)"
Thread 'Train Wreck Integral Shortcut...' Although this case is seemingly reasonable. I(1,2) x^3 dx [x^4/4](1,2) [x^2](1,2)[x^2/4](1,2)=9/4 I(1,2) x^3 dx [x^4/4](1,2)=15/4 View full post »
Although this case is seemingly reasonable. I(1,2) x^3 dx [x^4/4](1,2) [x^2](1,2)[x^2/4](1,2)=9/4 I(1,2) x^3 dx [x^4/4](1,2)=15/4