How to Integrate the Complementary Error Function with an Exponential Decay?

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SUMMARY

The integral of the complementary error function combined with an exponential decay, represented as \int_0^{\infty}\mbox{erfc}\left(\sqrt{\gamma}\right)\,\mbox{e}^{-\gamma}\,d\gamma, can be solved using substitution and integration by parts. Specifically, substituting \gamma = t^2 simplifies the integral to \int_0^{\infty} t \,\mbox{e}^{-t^2}\,dt. The solution employs Leibniz's rule for differentiation under the integral sign, facilitating the evaluation of the integral effectively.

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  • Understanding of the complementary error function (erfc)
  • Proficiency in integration techniques, specifically integration by parts
  • Familiarity with substitution methods in calculus
  • Knowledge of Leibniz's rule for differentiation under the integral sign
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  • Study the properties and applications of the complementary error function (erfc)
  • Explore advanced integration techniques, focusing on integration by parts
  • Learn about substitution methods in calculus for simplifying integrals
  • Investigate Leibniz's rule and its applications in integral calculus
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Students and professionals in mathematics, particularly those focusing on calculus and integral evaluation, as well as researchers dealing with error functions and exponential decay in their work.

EngWiPy
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Hello,

How to integrate the following integral (or what to use in the table of integrals):

\int_0^{\infty}\underbrace{\mbox{erfc}\left(\sqrt{\gamma}\right)}_{Complementary Error Function}\,\mbox{e}^{-\gamma}\,d\gamma?

Thanks in advance
 
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Substitute gamma = t^2 and then do a partial integration where you integrate te factor t exp(-t^2).
 


Count Iblis said:
Substitute gamma = t^2 and then do a partial integration where you integrate te factor t exp(-t^2).

It is solved straightforward by using integration by parts and the Leibniz's rule.

Thanks
 

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