How to Parameterize a Plane Between Two Given Planes

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Homework Help Overview

The problem involves finding parametric equations for a portion of the plane defined by the equation x + y = 1, constrained between the planes z = -1 and z = 1.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss how to express x and y in terms of a parameter, with suggestions for different parameterizations. There is a consideration of the relationship between x and y, and the implications of choosing different parameters.

Discussion Status

Participants are exploring various parameterization strategies, with some suggesting using x and z as parameters instead of x and y. There is a mix of interpretations regarding how to express the variables while adhering to the constraint of the plane equation.

Contextual Notes

Some participants question the necessity of two parameters for the surface parameterization, while others point out the dependence of y on x in the given equation.

ƒ(x)
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Homework Statement

Find parametric equations for the portion of the plane x+y = 1 that extends between the planes z = -1 and z = 1

The attempt at a solution

z = u -1[tex]\leq[/tex]u[tex]\leq[/tex]1

x = ?
y = ?
 
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Can you write x + y = 1 in parametric form? I.e., x = an expression in t (the parameter), y = another expression in t.

For z, all you need is -1 [itex]\leq[/itex] z [itex]\leq[/itex] 1. No parameter needed.
 
What do you mean?

I can have x and y equal anything as long as they both add up to 1
 
Like if I made x = 3t + t^2, then y = 1 - 3t - t^2
 
Why not let x = t? Why would you pick x = 3t + t^2?
 
To parameterize a surface you need two parameters. They can't be x and y in this problem because one of them determines the other. So try perhaps x and z as your parameters.

R(x,z) = < ?, ?, ?>

where you express the x, y, and z components in terms of x and z. It's really easy...
 

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