How to Prove det(xIm - AB) = xm-ndet(xIn - BA)?

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SUMMARY

The discussion centers on proving the equation det(xIm - AB) = xm-ndet(xIn - BA) for integers m ≥ n, where A is an m x n matrix and B is an n x m matrix. The proof involves understanding the characteristic polynomials and the eigenvalues of the matrix product AB. Sylvester's determinant theorem is referenced as a key tool in establishing this relationship, providing a structured approach to the proof.

PREREQUISITES
  • Understanding of linear algebra concepts, specifically determinants and eigenvalues.
  • Familiarity with matrix dimensions and properties of m x n and n x m matrices.
  • Knowledge of Sylvester's determinant theorem and its application in proofs.
  • Experience with characteristic polynomials in the context of matrix theory.
NEXT STEPS
  • Study Sylvester's determinant theorem in detail to understand its implications in matrix algebra.
  • Learn about eigenvalues and eigenvectors, particularly in relation to matrix products.
  • Explore characteristic polynomials and their role in determining matrix properties.
  • Practice proving similar determinant identities to reinforce understanding of the concepts.
USEFUL FOR

Mathematicians, students of linear algebra, and anyone interested in advanced matrix theory and determinant properties will benefit from this discussion.

brru25
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1. The problem statement

For integers m >= n,

Prove det(xIm - AB) = xm-ndet(xIn - BA) for any x in R.

Homework Equations



A is an m x n matrix
B is an n x m matrix

The Attempt at a Solution



I tried working out the characteristic polynomials by hand but it just seems too tedious for a nice proof. I know that each x is an eigenvalue of AB but after that I'm stumped.
 
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