Undergrad How to prove that a scalar potential exists if the curl of the vector point function is zero?

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A scalar potential exists if the curl of a vector point function is zero, as demonstrated by the closed curve integral being zero for any closed curve. This implies that the one-way integral between two points is path-independent, leading to a well-defined potential. By establishing a starting point, p_0, the integral values from this point to any other points can be calculated, confirming the existence of a scalar potential. The process relies on the properties of vector fields and their integrals over surfaces. Thus, the conditions for a scalar potential are satisfied when the curl of the vector field is zero.
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scalar potential can be obtained by integrating the vector point function whose curl is zero but how to arrive at this result that a potential exist
 
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First show that if ##\mathrm{rot}\, v=0## then ##\int_Cv_xdx+v_ydy+v_zdz=0## for any closed curve ##C##. To do that
consider a 2-dimensional surface ##S## such that ##\partial S=C##
 
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immortalsameer13 said:
scalar potential can be obtained by integrating the vector point function whose curl is zero but how to arrive at this result that a potential exist
Because the closed curve integral is zero, the one-way integral from one point to another has only one answer no matter which path is taken. So the one-way integral gives you a well-defined definition of the potential.

ADDED: Establish a starting point, ##p_0##, for the beginning of a path to any and all other points. The integral values from ##p_0## to the other points gives a well-defined potential at those points.
 
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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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