How to prove that the sum of two rotating vectors in an ellipse?

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To determine the orientation of the major axis of the ellipse formed by two rotating vectors in the xy-plane, the vectors P and Q, with lengths specified and rotating in opposite directions, must be analyzed. The expressions for the vectors should use their actual lengths rather than absolute values. By expanding the cosine and sine terms for the resultant X and Y components, one can group terms involving cos(ωt) and sin(ωt). The key insight is that at a specific moment, the vectors align, resulting in the maximum length of the resultant vector, which indicates the direction of the major axis. This approach simplifies finding the orientation relative to the x-axis.
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Homework Statement



Within the xy-plane, two vectors having lengths P and Q rotate around the z-axis with angular velocities ω and –ω. At t = 0,these vectors have orientations with respect to the x-axis specified by θ1 and θ2. How do I find the orientation of the major axis of the resulting ellipse relative to the x-axis.


The Attempt at a Solution



P=|p|cos(θ1+ωt) x^+ |p|sin(θ1+ωt) y^
Q=|q|cos(θ1+ωt) x^+ |q|sin(θ1+ωt) y^

x^- x hat
y^-y hat

How do I solve this after these 2 equations?
I tried to group the x and y vectors separately. But i could not figure out anything after that.

X= |p|cos(θ1+ωt)+|q|cos(θ1+ωt)
Y=|p|sin(θ1+ωt)+ |q|sin(θ1+ωt)

Without the θ terms I could have just squared both sides and added it. But now I am stuck. Thank you for the help :)
 
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ppoonamk said:

Homework Statement



Within the xy-plane, two vectors having lengths P and Q rotate around the z-axis with angular velocities ω and –ω. At t = 0,these vectors have orientations with respect to the x-axis specified by θ1 and θ2. How do I find the orientation of the major axis of the resulting ellipse relative to the x-axis.

The Attempt at a Solution



P=|p|cos(θ1+ωt) x^+ |p|sin(θ1+ωt) y^
Q=|q|cos(θ1+ωt) x^+ |q|sin(θ1+ωt) y^

x^- x hat
y^-y hat

How do I solve this after these 2 equations?
I tried to group the x and y vectors separately. But i could not figure out anything after that.

X= |p|cos(θ1+ωt)+|q|cos(θ1+ωt)
Y=|p|sin(θ1+ωt)+ |q|sin(θ1+ωt)

Without the θ terms I could have just squared both sides and added it. But now I am stuck. Thank you for the help :)

The expressions are not correct.
The vectors have length P and Q, use them instead of |p| and |q|.
The vectors rotate in opposite directions (the angular velocities are ω and -ω).
One vector encloses θ1 angle with the x-axis at t=0, the other one encloses θ2.

Expand the cosine and sine terms in the expression for X and Y, collect the terms with cos(ωt) and sin(ωt).
There is an easy method to find the angle of the principal axis: Just think that the vectors rotate in opposite directions, and there is a time instant when they are on the same line, so the resultant has the longest length.
ehild
 
Last edited:
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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