MHB How to Prove the Lagrange Interpolation Formula?

Click For Summary
The discussion centers on proving the Lagrange interpolation formula, specifically showing that the sum of products of a polynomial evaluated at nodal points and the Lagrange basis functions equals the polynomial itself. Participants express uncertainty about how to initiate the proof, indicating familiarity with Lagrange polynomials but lacking clarity on the proof's structure. Key points include the need to understand the properties of Lagrange basis functions and their role in polynomial interpolation. The conversation emphasizes the importance of establishing the relationship between the polynomial and its interpolating form. Overall, the thread seeks guidance on effectively starting the proof process.
HMPARTICLE
Messages
95
Reaction score
0
$\text{Let } L_{n,i}, i = 0,...,n, \text{be the Lagrange nodal basis at} x_0 < x_1<...<x_n$. Show that, for any polynomial $q \in P_n$

$$\sum_{i=0}^nq(x_i)L_{n,i}(x)= q(x)$$

I don't know how to begin this proof. I know what a lagrange polynomial is, but I am not sure how to begin. If someone could give me a point to start please.
 
Physics news on Phys.org
Are you need to prove interpolation formula of Lagrange?
 
Thread 'How to define a vector field?'
Hello! In one book I saw that function ##V## of 3 variables ##V_x, V_y, V_z## (vector field in 3D) can be decomposed in a Taylor series without higher-order terms (partial derivative of second power and higher) at point ##(0,0,0)## such way: I think so: higher-order terms can be neglected because partial derivative of second power and higher are equal to 0. Is this true? And how to define vector field correctly for this case? (In the book I found nothing and my attempt was wrong...

Similar threads

  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 40 ·
2
Replies
40
Views
3K
  • · Replies 52 ·
2
Replies
52
Views
4K
Replies
27
Views
2K
Replies
48
Views
4K
  • · Replies 1 ·
Replies
1
Views
676
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 21 ·
Replies
21
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K