How to Prove the Weighted Centroid Formula for Parallel Forces?

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SUMMARY

The discussion centers on proving the weighted centroid formula for parallel forces, specifically demonstrating that two weights, W and 3W, acting at points P1 and P2, respectively, are equivalent to a single weight of 4W acting at point P. The relationship between the distances is defined as P1 P : P P2 = 3 : 1. The formula OC = (Ʃi opi.Fi) / (ƩFi) is crucial in this proof, where OC represents the centroid's position, and the forces are treated as vectors. Participants emphasize the importance of selecting an appropriate origin for the calculations.

PREREQUISITES
  • Understanding of vector forces and their representation
  • Familiarity with the concept of centroids in physics
  • Knowledge of the weighted average formula
  • Basic algebra for manipulating equations
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  • Study the derivation of the weighted centroid formula in detail
  • Explore vector addition and its implications in physics
  • Learn about the application of centroids in engineering mechanics
  • Investigate examples of parallel forces in real-world scenarios
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Students in physics or engineering, educators teaching mechanics, and professionals involved in structural analysis or force systems will benefit from this discussion.

BigCheese234
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Given the formula for the weighted centroid, C of a system of parallel forces
Fi acting at points Pi, show that two weights W and 3W, acting respectively
at points P1, P2, are together equivalent to a single weight 4W acting at P,
where P lies on the line segment joining P1 to P2 and P1 P : P P2 = 3 : 1.OC = (Ʃi opi.Fi)/ (ƩFi)Any one know how to prove it ? revising and this came up in a test last year its not in my notes?
 
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Is that the formula as you're given it? The forces are vectors, so it would more logically be written
OC. (ƩFi) = (Ʃi opi.Fi)
You have the choice of where to place the origin. Where will you place it? Having done that, can you fill in the RHS of the formula using the W & 3W set-up?
 

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