How to re-write this expression?

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kaffekjele
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Could someone please help me make this expression a little smaller? I'm sure there are things that cancels out or could be re written, but I generally suck at these things as I tend to break a few math rules along the way.
Could I for instance cancel n against n in the two last cosine expressions so I'm left with -cos∏-cos∏/2 at the end?

Expression is here: http://tinypic.com/r/2lw8047/6
 
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kaffekjele said:
Could someone please help me make this expression a little smaller? I'm sure there are things that cancels out or could be re written, but I generally suck at these things as I tend to break a few math rules along the way.
Could I for instance cancel n against n in the two last cosine expressions so I'm left with -cos∏-cos∏/2 at the end?

Expression is here: http://tinypic.com/r/2lw8047/6

Absolutely NOT! ##\cos(n \pi)/n## is most definitely not equal to ##\cos(\pi).## Just evaluate ##\cos(n \pi)/n## for ##n = 2, 3, 4## and see what you get.

Vital advice: put out of you mind forever any thought that you can cancel n's in such situations. Never try to cancel the n's in expressions like ##\cos(nx)/n, \; \sin(nx)/n, \: e^{nx}/n, \; \log(nx)/n, ## etc. You just cannot do it.
 
To add to what Ray said, you can give expressions for ##\cos (n\pi)## and ##\cos(\frac{n\pi} 2)## that don't involve cosines. Write them out for a few values of ##n## to see a pattern.