1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Eliminate the denominator in this expression

  1. Aug 23, 2013 #1
    1. The problem statement, all variables and given/known data
    Eliminate the denominator on the RHS of the following expression
    [tex]sin(\alpha)-sin(\beta) = -\frac{-v(sin(\alpha) cos(\alpha) + sin(\alpha) cos(\beta)}{c-vcos(\alpha)}[/tex]
    and from it, derive
    [tex]sin(\alpha)-sin(\beta) = -\frac{v}{c}(sin(\alpha)cos(\beta)+sin(\beta)cos(\alpha))[/tex]

    2. Relevant equations
    For a bit of context, this is from a multipart derivation of the relativistic reflection law based on the principle of least time. I'm assuming that you don't need to know what the sines and cosines in terms of the lengths of the triangles because the hint says to 'multiply through' (and substituting back in lengths hasn't made it any better), but I've attached the diagram I'm working from anyway.


    3. The attempt at a solution
    Some things I've tried:
    - worked backwards from the RHS expression in the second equation to see if I could find what to multiply by
    - multiplied by top and bottom by [itex]c+vcos(\alpha)[/itex]
    - tried writing [itex]sin(\alpha)[/itex] and [itex]cos(\alpha)[/itex] as the ratios of the lengths in hopes of getting a [itex]sin(\beta)[/itex] and [/itex]sin(\alpha)[/itex] back out of it. This is what I got:

    [tex]-\frac{v}{c}(\frac{x(cos(\alpha)+cos(\beta))}{\sqrt{(d_0+vt_a)^2+x^2)}-v(d_o+vt_a)})[/tex]

    --
     

    Attached Files:

  2. jcsd
  3. Aug 23, 2013 #2
    I think I can help you, just tell me, there is missing one bracket on the RHS, could you please tell me where it should be?
     
  4. Aug 23, 2013 #3

    ehild

    User Avatar
    Homework Helper
    Gold Member

    There is a parenthesis missing from the end of the RHS of the first equation.

    Just multiply the whole equation with the denominator, expand and simplify.


    ehild
     
  5. Aug 23, 2013 #4
    Ah I got it now, thanks ehild and Electric Red.

    Somewhere along the line, I got the idea that to solve an equation we weren't allowed to multiply it by anything other than one or else we change it somehow...though it makes sense now because if we multiply both sides by the same factor then it'll just cancel in the end...
     
  6. Aug 24, 2013 #5

    ehild

    User Avatar
    Homework Helper
    Gold Member

    When you multiply with an expression you have to exclude the cases when it is zero. So you say: Multiply by c-vcos(α) ≠ 0. Here it is sure as v∠c and cos(α) ≤1.

    ehild
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Eliminate the denominator in this expression
Loading...