MHB How to Rewrite Absolute Value Expressions Without Absolute Values?

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The discussion focuses on rewriting the expression |x + 3| + 4|x + 3| for x < -3 without using absolute values. It establishes that for x < -3, |x + 3| equals -(x + 3). The correct transformation leads to 5|x + 3| being rewritten as -5(x + 3), simplifying to -5x - 15. Participants clarify that combining terms and maintaining the correct operations is essential in the rewriting process. The final expression is presented as -5(x + 3), effectively eliminating the absolute value.
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The | x | = x when x > or = 0.

The | x | = - x when x < 0.

Rewrite the following expression in a form that does not contain absolute value.

| x + 3 | + 4 | x + 3 |, where x < -3

-(x + 3) + 4 -(x + 3)

-x - 3 + 4 - x - 3

-2x - 6 + 4

-2x - 2

Correct?
 
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RTCNTC said:
The | x | = x when x > or = 0.

The | x | = - x when x < 0.

Rewrite the following expression in a form that does not contain absolute value.

| x + 3 | + 4 | x + 3 |, where x < -3

-(x + 3) + 4 -(x + 3)

-x - 3 + 4 - x - 3

-2x - 6 + 4

-2x - 2

Correct?

No, you've turned multiplication into addition...we are given the expression:

$$|x+3|+4|x+3|$$ where $$x<-3$$

Now, the first thing I would do is combine like terms:

$$5|x+3|$$

Let's look at:

$$x<-3$$

Add 3 to both sides:

$$x+3<0$$

And so our expression becomes:

$$5(-(x+3))=-5(x+3)$$

We can stop here because we have rewritten the expression in a form not involving absolute value, and there's no need to distribute in my opinion. :D
 
|x + 3 | + 4 | x + 3 |, where x < -3

-(x + 3) - 4(x + 3)

-x - 3 - 4x - 12

-5x - 15

-5(x + 3)
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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