How to Show Linearity of a Function?

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To demonstrate the linearity of the function operator ∂ from V_{n+1} to V_n, it is essential to show that ∂(f_1 + f_2) equals ∂(f_1) + ∂(f_2) and that ∂(αf) equals α∂(f) for any functions f_1, f_2 in V_{n+1} and scalar α in K. The operations involved are pointwise, meaning that the addition and scalar multiplication are performed at each point in the domain. The discussion highlights the need for clarity regarding the properties of the function f, as it does not necessarily have to be linear itself. Understanding the operator ∂ and its transformation of functions is crucial for tackling the problem effectively. The conversation emphasizes the importance of grasping abstract mathematical concepts to approach such problems confidently.
PhysicsRock
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Homework Statement
Take the Vector space of functions from a set ##\{ 0,1,...,n \}## to a field ##K##, ##V_n = \text{Fun}(\{ 0,1,...,n \},K)##. The notation ##j_K## refers to ##\underbrace{1_K + ... + 1_K}_{j \text{-times}}##. Let ##f \in V_{n+1}##. For a function ##\partial : V_{n+1} \rightarrow V_n## and ##f \in V_{n+1}##, show that ##\partial## is a linear function for ##\partial : i \rightarrow (i+1)_K \cdot f(i+1)##.
Relevant Equations
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I don't really know how I am supposed to approach that. In general, I know how to show that a function is linear, which is to show that ##f(\alpha \cdot x) = \alpha \cdot f(x)## and ##f(x_1 + x_2) = f(x_1) + f(x_2)##. However, for this specific function, I have no idea, since there is nothing provided about ##f##, so if I wanted to show the multiplicative property, I couldn't just drag anything out of ##f## without loss of generality. So I could really use some help to figure this out.

Thank you in advance.
 
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PhysicsRock said:
Homework Statement:: Take the Vector space of functions from a set ##\{ 0,1,...,n \}## to a field ##K##, ##V_n = \text{Fun}(\{ 0,1,...,n \},K)##. The notation ##j_K## refers to ##\underbrace{1_K + ... + 1_K}_{j \text{-times}}##. Let ##f \in V_{n+1}##. For a function ##\partial : V_{n+1} \rightarrow V_n## and ##f \in V_{n+1}##, show that ##\partial## is a linear function for ##\partial : i \rightarrow (i+1)_K \cdot f(i+1)##.
Relevant Equations::

Should this not be <br /> \partial(f) : i \mapsto (i+1)_K \cdot f(i+1)

EDIT: Also, I think we need \partial: V_{n} \to V_{n+1} for \partial(f)(n) to be defined.

I don't really know how I am supposed to approach that. In general, I know how to show that a function is linear, which is to show that ##f(\alpha \cdot x) = \alpha \cdot f(x)## and ##f(x_1 + x_2) = f(x_1) + f(x_2)##. However, for this specific function, I have no idea, since there is nothing provided about ##f##, so if I wanted to show the multiplicative property, I couldn't just drag anything out of ##f## without loss of generality. So I could really use some help to figure this out.

You are trying to show that \partial : V_{n+1} \to V_n is linear, ie. \partial(f_1 + f_2) = \partial (f_1) + \partial (f_2) for all f_1, f_2 \in V_{n+1} and \partial(\alpha f) = \alpha \partial (f) for every \alpha \in K and every f \in V_{n+1}.

The operations on V_{n+1} and V_n are pointwise: (f_1 + f_2)(x) = f_1(x) + f_2(x), (\alpha f)(x) = \alpha f(x).
 
Last edited:
pasmith said:
Should this not be <br /> \partial(f) : i \mapsto (i+1)_K \cdot f(i+1)
You are trying to show that \partial : V_{n+1} \to V_n is linear, ie. \partial(f_1 + f_2) = \partial (f_1) + \partial (f_2) for all f_1, f_2 \in V_{n+1} and \partial(\alpha f) = \alpha \partial (f) for every \alpha \in K and every f \in V_{n+1}.

The operations on V_{n+1} and V_n are pointwise: (f_1 + f_2)(x) = f_1(x) + f_2(x), (\alpha f)(x) = \alpha f(x).
Yes, it's supposed to be ##\partial(f)##. Thank you, I forgot to state that. This helps.
 
pasmith said:
Should this not be <br /> \partial(f) : i \mapsto (i+1)_K \cdot f(i+1)

EDIT: Also, I think we need \partial: V_{n} \to V_{n+1} for \partial(f)(n) to be defined.
You are trying to show that \partial : V_{n+1} \to V_n is linear, ie. \partial(f_1 + f_2) = \partial (f_1) + \partial (f_2) for all f_1, f_2 \in V_{n+1} and \partial(\alpha f) = \alpha \partial (f) for every \alpha \in K and every f \in V_{n+1}.

The operations on V_{n+1} and V_n are pointwise: (f_1 + f_2)(x) = f_1(x) + f_2(x), (\alpha f)(x) = \alpha f(x).
But one thing I don't understand: how do you know that ##f## obeys the requirements of a linear function?
 
PhysicsRock said:
But one thing I don't understand: how do you know that ##f## obeys the requirements of a linear function?

f doesn't have to be linear; its domain is not even a vector space!
 
pasmith said:
EDIT: Also, I think we need ##\partial : V_n \rightarrow V_{n+1}## for ##\partial(f)(n)## to be defined.

I thought about that too. The assignment though says clearly what I stated in the problem description.
 
The problem statement asks you to show that \partial is linear; it says nothing about f, other than that it is an arbitrary vector in V_n. Perhaps the fact that you used it in your statement of the definition of a linear function is confusing you.
 
pasmith said:
The problem statement asks you to show that \partial is linear; it says nothing about f, other than that it is an arbitrary vector in V_n. Perhaps the fact that you used it in your statement of the definition of a linear function is confusing you.
I pretty much only translated the assignment. I felt like including everything was helpful to receive the needed aid.
 
PhysicsRock said:
I pretty much only translated the assignment. I felt like including everything was helpful to receive the needed aid.
When you have something as abstract as this, you need to get a grip on what everything is.

I would have called ##\partial## an operator that maps functions in ##V_{n+1}## to functions in ##V_n##.

For ##f \in V_{n+1}##, what does ##d = \partial(f)## look like?

We know that ##d \in V_n## must be defined for ##i = 0, 1 \dots n##. Working from the definition:
$$d(0) = 1_Kf(1)$$$$d(1) = 2_Kf(2)$$$$\dots d(n) = (n+1)_Kf(n+1)$$Now that we see how ##\partial## transforms functions the fun can begin!

Let ##f, g \in V_{n+1}## and ##a \in K##. We need to show that:
$$\partial(f +g) = \partial(f) + \partial(g)$$$$\partial(af) = a\partial(f)$$Perhaps that's more help than I should have given you. It seems to me that the material you're studying exceeds your current capability to think in terms of abstract mathematics.
 

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