How to Simplify a Series with Basic Algebra?

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kuahji
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[tex]\sum[/tex] (2^(2n)-(-7)^n)/(11^n)

The book has that expression equal to
[tex]\sum[/tex] (4/11)^n - [tex]\sum[/tex] (-7/11)^n

I'm not seeing how the first part changes to (4/11)^n. Wouldn't it be (2^2+2^n) & not 4^n? Or is there something else I'm missing?
 
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Fact:
[tex](x^y)^z = x^{yz}[/tex].
Does that help you out?
 
Crude, nm. 2am & math doesn't mix sometimes. ^_^