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**1. prove that:**

X'Y'Z + X'YZ' + XY'Z' + XYZ = (X⊕Y)⊕Z

X'Y'Z + X'YZ' + XY'Z' + XYZ = (X⊕Y)⊕Z

## Homework Equations

Use postulates and theorems.

## The Attempt at a Solution

X'Y'Z + X'YZ' + XY'Z' + XYZ (original expression)

X'Y'Z + X'YZ' + X(Y'Z' + YZ) (distributive)

X'Y'Z + X'YZ' + X.1 (complement)

X'Y'Z + X'YZ' + X (identity)[/B]

**need help.**

also may you expand the expression:

also may you expand the expression

**(X⊕Y)⊕Z**

I think it is like this: (XY' + X'Y)(ZXY' +Z'X'Y)

but i do not know if it's right