How to Simplify the Expression sin60° + sin20°?

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SUMMARY

The expression sin60° + sin20° simplifies to 2sin(40°)cos(20°) using the sum-to-product formulas in trigonometry. The correct application of the identity sin(a) + sin(b) = 2sin((a+b)/2)cos((a-b)/2) is crucial for this simplification. The discussion highlights the importance of understanding trigonometric identities for effective problem-solving in trigonometry. Participants also sought clarification on related transformation formulas, demonstrating the interconnectedness of trigonometric concepts.

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  • Familiarity with sine and cosine functions.
  • Basic algebraic manipulation skills.
  • Knowledge of angle addition and subtraction in trigonometry.
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  • Learn about transformation formulas for sine and cosine functions.
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Students studying trigonometry, educators teaching trigonometric identities, and anyone looking to enhance their problem-solving skills in trigonometric expressions.

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[SOLVED] Simplifying Trig Products

Homework Statement


Express the following as a product and simplify.
sin60° + sin20°


Homework Equations





The Attempt at a Solution



I don't understand what the question is trying to say. For example, do I convert sin60° and then add. I don't understand. Someone please help.
 
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So, \sqrt{3}/2 + sin20°
= 1.208

Could this be right?
 
Last edited:
Thanks Evalesco.

So, here it is:

sin60° + sin20° = 2sin(60+20/2)cos(60+20/2)

Is this right?

Also, because of the fact that you pointed this to me, there is another question I have.

The question states:
Using the method developed in Example 3 (my note: we don't have the book so we don't know what this method is) of this section, prove each of the following Transformation Formulas.

sinx - siny = 2cos(x+y/2)sin(x-y/2)

Could someone please help me with this? Also, thanks Evalesco and Moridin for helping me out.
 
sin60° + sin20° = 2sin(60+20/2)cos(60+20/2)

Not quite; apply the correct formula under the headline "Sum-to-Product Formulas" and do not forget the signs or what should be divided with two.
 
http://hh4.hollandhall.org/kluitwieler/pages/Advanced_Trig/Trig%20Frog%20Homepage/sumtoproduct.htm

About 10 seconds ago, I looked at the above webpage.

Here is what I came up with now:

sin60° + sin20° = 2sin40°cos20°

I hope finally it is correct.

Also, can you please help me with my second question which I posted in the last post? Thanks.
 
Last edited by a moderator:
Yes, I finally got it.

sin60° + sin20° = 2sin((x+y)/2)cos((x-y)/2)

A + B = 60°
A - B = 20°
---------- +
2A = 80°
A = 40°

A + B = 60°
A - B = 20°
---------- -
2B = 40°
B = 20°

sin60° + sin20° = 2sin(40°)cos(20°)

Yes, I finally got it. But could there have been an easier way? Or is this good enough? I tried my best anyways.

Thanks to Evalesco and Moridin for helping me out.
 

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