(adsbygoogle = window.adsbygoogle || []).push({}); Let f(t)=( (cos t)^3, (sin t)^3 )

Let S = {f(t) | t E R}

Draw a sketch of S.

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Now I know that S is x^(2/3) + y(2/3) = 1

What is the fastest way to draw a really rough sketch of this? (bascially I need the shape) I am very lost in situations like this. I was never taught how to do quick sketch on graphs like this one...(no graphing calculators allowed, of course)

Please help me! Thanks!

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# How to sketch x^(2/3) + y(2/3) = 1 ?

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