How to Solve Differential Equations for Homework?

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Homework Help Overview

The discussion revolves around solving differential equations, specifically focusing on a problem involving the relationship between variables represented as x and y. The original poster expresses uncertainty about how to approach a particular part of the problem.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the interpretation of variables and the meaning of notation, such as "x dot" indicating differentiation with respect to time. There are attempts to derive solutions and clarify the steps involved in integrating the equations.

Discussion Status

Participants are actively engaging with each other's reasoning, providing feedback on attempts and clarifying misunderstandings. Some guidance has been offered regarding the integration process, and there is an ongoing exploration of different interpretations of the equations involved.

Contextual Notes

There is mention of confusion regarding the roles of x and y in the equations, which may affect the understanding of the problem. Additionally, the discussion includes references to specific integral forms and their implications for the solution.

pat666
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Homework Statement



see attached


Homework Equations





The Attempt at a Solution


Question 7a) I can do but 7b I am not sure how to start.
I think x with a dot means differential with respect to time? need some help starting.

Thanks
 

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Yes, x dot=dx/dt. It's separable.
 
Thanks Dick,
this question is confusing because x is y. anyway I have
x=sqrt(4t^2+8C)?THANKS
 
pat666 said:
Thanks Dick,
this question is confusing because x is y. anyway I have
x=sqrt(4t^2+8C)?THANKS

That's not what I get from dx/dt=4*x*t. Can you explain how you got it?
 
from text:
dy/dx=f(x)g(y)
then int(1/g(y) .dy = int(f(x).dx int is integral
f(t)=t
g(x)=4x
then int(1/4x.dx)=int(t.dt)
x^2/8=t^2/2+C

so x=sqrt(4t^2+8C)

like I said this question is really confusing me because x is where y normally is.
 
int(1/(4x)*dx)=int(t*dt) is good. The right side is t^2/2+C. That's also good. But, the left side isn't x^2/8. Don't you get a log? int((1/x)*dx) is log(x) in my book.
 
Yes you do, my bad. so it should be ln(x)/4=t^2/2+C
so x=e^(2t^2+4c)??
 
pat666 said:
Yes you do, my bad. so it should be ln(x)/4=t^2/2+C
so x=e^(2t^2+4c)??

That looks much better.
 
Sweet, THANKS
 

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