How to Solve Elastic Collision Problems?

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SUMMARY

The discussion focuses on solving an inelastic collision problem involving two vehicles: a red convertible and a green sedan, both with a momentum of 2200 kg·m/s. The initial speeds of both vehicles are 14 m/s, with the red car traveling north and the green car traveling west. The resulting momentum must be calculated using the equation m1u1 + m2u2 = m1v1 + m2v2, taking into account that inelastic collisions result in the vehicles moving together post-collision. The final momentum direction is determined by vector addition in a two-dimensional space.

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  • Understanding of momentum conservation principles
  • Familiarity with vector addition in two dimensions
  • Knowledge of inelastic collision characteristics
  • Ability to apply equations of motion in physics
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Homework Statement



10. A red convertible of momentum mv traveling north on the Murdoch Drive collides, at the intersection of Murdoch Dr and South St, with a green sedan having the same magnitude of momentum, but traveling west on South St.

a. What is the magnitude and direction of the resulting momentum of the vehicles if it is an inelastic collision?

b. Calculate the resulting momentum if the mass of each vehicle is 2200kg and their initial speeds were both 14ms-1


Homework Equations


m1u1 +m2u2 = m1v1 +m2v2

P1i + P2i = P1f + P2f



The Attempt at a Solution




a.
red car goes west

green cars goes north



b.

2200.14 + 2200.14 = m1v1 +m2v2
er that is as far as i got because i am confused?
 
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This isn't a 1D problem. If you take a better look at it you will see that it's in 2D, so try to draw yourself a picture. And one more thing. If it's an inelastic collision then the cars will continue to move as one with one speed which will be common for both of them.
 


do you mean that they will both go in the same direction because i thought that was a perfactly elastic collision...does that mean i am also using the wrong equation?
 


By definition, if there is an elastic collision, both objects will bounce one of each other and each will go in their own direction with their own speed.

You are given a inelastic collision, so there will be no bouncing and the 2 cars could be observers as a single object which goes in a direction different from the initial directions of both cars.

The general idea you have is OK, but you need to draw the picture to realize that the speeds are not on the same line.
 


i have drawn a picture and i know they don't crash head on but i don't see how you can predict the final directions there only way i know how to work out which direction they going is when you know which car as more force? Is equation i am using right?

if so how come there is not enough data in the question to complete it?
 


Hint: Both velocity and momentum are vectors and should be dealt with accordingly.
You have one car moving north with speed 14m/s, so his speed in 2D is 14j m/s
The other car is moving west, so his speed is -14i m/s.
 


ok if two cars are going in any direction not matter what directiion as long as they are not the same then one speed is negative
 


Ok, here's the picture before collision. You should be able to visualize what I was trying to say to you. You need to look at this matter in 2D, because the cars are not on the same track.

http://img8.imageshack.us/img8/2686/beforeead.jpg
 
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