How to solve for q after finding derivative (derived) equation?

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I have started with the formula.

T = 0.5q+4q^(-1/2)+9/q

I have derived and am trying to solve for q but have gotten caught up on how to solve when I have to subtract two variables with different base numbers and different exponents.

2aj3l7q.jpg


Any ideas?
 
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noid said:
I have started with the formula.

T = 0.5q+4q^(-1/2)+9/q

I have derived and am trying to solve for q but have gotten caught up on how to solve when I have to subtract two variables with different base numbers and different exponents.

Handwritten working in blue ink: T = 0.5q + 4q^(-1/2) + q/q, with the labels 'number (nine)' and 'variable (letter)' pointing to the terms. Below it, T = 0.5 - 2q^(-3/2) - 9q^(-2), then 'Solve for q', then 0.5 - 2q^(-3/2) - 9q^(-2) = 0, and -2q^(-3/2) - 9q^(-2) = -0.5.


Any ideas?

For one thing you made a mistake to start. If you divide both sides by q then the left side should be T/q. The correct way to go is probably to set q^(-1/2)=w, then express the other powers of q in terms w. If you work it through you'll get a quartic equation in w, a polynomial equation with w^4 as the highest power. The good news is that in principle, has a analytic solution. The bad news is that it's so complex as to to be basically useless. Are you sure you haven't made a mistake in deriving the equation you showed us? Where did it come from??
 
Sorry for the misunderstanding: The second line is actually the derivative in respect to q of the first line (I forgot to put ' after T). Then from the second line I want to find what q is (after setting T to 0).
 
noid said:
Sorry for the misunderstanding: The second line is actually the derivative in respect to q of the first line (I forgot to put ' after T). Then from the second line I want to find what q is (after setting T to 0).

Ah, ok. I should have spotted that. If you don't have a T in it then you can still change it into a quartic equation in w. Then you could hope it factors, but I don't think it does. If not you'll just have to find the roots numerically.