MHB ็How to Solve the system of equation

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The discussion focuses on solving a system of equations involving variables \(x_0\), \(\phi\), and \(\gamma\). The equations presented are \(x_0\cos(\phi) = 2.78\), \(x_0\sin(\phi)=2.78 \left( \frac{\gamma^2/2}{ \sqrt{10-\frac{\gamma^2}{4}}} \right)\), and \(x_0e^{-15\gamma} \cos\left(30\sqrt{10-\frac{\gamma^2}{4}}-\phi\right)=1\). The recommended approach is to divide the second equation by the first to eliminate \(x_0\), yielding a new equation in terms of \(\phi\) and \(\gamma\). A similar division of the third equation by the first is suggested to derive another equation involving the same variables.

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$$x_0\cos(\phi) = 2.78$$
$$x_0\sin(\phi)=2.78 \left( \frac{\gamma^2/2}{ \sqrt{10-\frac{\gamma^2}{4}}} \right)$$
$$x_0e^{-15\gamma} \cos\left(30\sqrt{10-\frac{\gamma^2}{4}}-\phi\right)=1$$

I don't know awsner of $$\phi , x_,\gamma$$
 
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Start by dividing the second equation by the first. That removes "[math]x_0[/math]" leaving an equation in \phi and \gamma. Then divide the third equation by the first to also remove x_0 and get another equation in \phi and \gamma.
 

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