- #1

Another1

- 40

- 0

\(\displaystyle x_0\sin(\phi)=2.78 \left( \frac{\gamma^2/2}{ \sqrt{10-\frac{\gamma^2}{4}}} \right)\)

\(\displaystyle x_0e^{-15\gamma} \cos\left(30\sqrt{10-\frac{\gamma^2}{4}}-\phi\right)=1\)

I don't know awsner of \(\displaystyle \phi , x_,\gamma\)