How to subnet in third octet IPv4

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SUMMARY

This discussion focuses on subnetting Class B IPv4 addresses, specifically addressing the challenges of spacing address blocks in the third octet for networks below /24. The example provided uses the IP address 150.53.218.209/19, where the first 19 bits identify the network and the last 13 bits identify the client. To determine the network number, all bits from bit 20 to bit 32 must be set to zero. The confusion arises due to the presence of 1's in the binary representation of the third and fourth octets, limiting available addresses.

PREREQUISITES
  • Understanding of Class B IPv4 addressing
  • Familiarity with CIDR notation and subnetting concepts
  • Knowledge of binary representation of IP addresses
  • Experience with calculating network numbers and usable host ranges
NEXT STEPS
  • Learn how to calculate subnet masks for Class B addresses
  • Study the process of determining usable host ranges in IPv4 subnetting
  • Explore subnetting tricks for Class A and B addresses
  • Practice subnetting exercises using various CIDR notations
USEFUL FOR

This discussion is beneficial for network engineers, IT professionals, and students learning about IPv4 subnetting, particularly those focusing on Class B addressing and network design.

itlivesthere
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I already know how to subnet Class C addresses. Class B subnetting isn't proving to be very difficult, except for one little thing. I'm confused about how to space out the address blocks in the third octet when dealing with networks below /24.

Here's an example that I'm having trouble with:

Given the IP address 150.53.218.209/19 provide:
Network Number:
First Usable Host:
Last Usable Host:
Broadcast:
The reason this confuses me is that the third and fourth octets are already mostly made of 1's (binary), therefore doesn't that mean not many addresses are available right off the rip?
Also, if anyone has some easy-to-memorize tricks to subnet Class B and A addresses that I can do with paper and pencil I would greatly appreciate the help!
 
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Welcome to PF, itlivesthere! :smile:

The first 19 bits identify the network (subnet), the last 13 bits identify the client.
To find the network number, you need to set all bits from bit 20 up to bit 32 to zero.
 

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