How to Transform a Piecewise Function Using the Second Shift Theorem?

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The discussion focuses on transforming a piecewise function into a unit step function and finding its Laplace transform. The piecewise function is defined as t(e^t) for 0≤t≤5 and 0 for t≥3. The initial approach suggests using the unit step function, but there is confusion regarding the correct formulation. A participant points out that the second equation presented is incorrect and emphasizes the importance of working through the transformation step-by-step. The conversation highlights the need for careful calculations in applying the Second Shift Theorem.
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questions asks to write the piecewise function as a unit step function and then to find the laplace transform

t(e^t) 0≤t≤5
0 t≥3

I know it should be along the lines of

t(e^t) - t(e^t)u(t-5)

which then goes to

t(e^t) - (t-5)(e^(t-5))u(t-5)

I know there should be more to the above equation but I just can't figure out what to do from here
 
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robmass said:
questions asks to write the piecewise function as a unit step function and then to find the laplace transform

t(e^t) 0≤t≤5
0 t≥3

I know it should be along the lines of

t(e^t) - t(e^t)u(t-5)

which then goes to

t(e^t) - (t-5)(e^(t-5))u(t-5)

I know there should be more to the above equation but I just can't figure out what to do from here

Your second equation is wrong: you do not get simply (t-5)(e^(t-5))u(t-5). Work everything out carefully, step-by-step.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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