Finding the 12th root of a number on a scientific calculator

[goosey00]

On a scientific calculator, how do you get a root of a number for an exponiental? Ex.-.653846^1/12=
I was taking 1/12 and making it so I can make it exponent for .653846. Obviously wrong. What am I doing here??

 

[SuperSonic4]

Re: exponiental problem

On a scientific calculator, how do you get a root of a number for an exponiental? Ex.-.653846^1/12=
I was taking 1/12 and making it so I can make it exponent for .653846. Obviously wrong. What am I doing here??

Largely depends on what calculator you have. On my Casio fx-83ES one would type

-0.653846 x[sup]y[/sup] ( 1 / 12)

although y is a box - can't show it on my keyboard.

 

[goosey00]

Re: exponiental problem

Largely depends on what calculator you have. On my Casio fx-83ES one would type

-0.653846 x[SUP]y[/SUP] ( 1 / 12)

although y is a box - can't show it on my keyboard.

Im still getting it wrong though. What do you get to check the answer

 

[goosey00]

Re: exponiental problem

Maybe it's how I'm asking. It says simplify b=(squiggy equal sign).653846^1/12

 

[goosey00]

Re: exponiental problem

Got it! Thank you!

 

[Jameson]

Re: exponiental problem

Got it! Thank you!

Hi goosey00,

Welcome to MHB! :) When you make a post you might notice a yellow column on the right hand side. If you look to the top of this column and click "Scientific Calculator" then a calculator will popup where you can practice making these calculations. What did you get for your final answer?

Jameson

 

[goosey00]

stuck again

Purchasing power=

For the orginal purchasing power f(t)=1.08 (.926127)
For the one part I got at f(t)= .40 (.931511)
They want me to know where they intersect. If you need more info, let me know

 

[Jameson]

Re: stuck again

Purchasing power=

For the orginal purchasing power f(t)=1.08 (.926127)
For the one part I got at f(t)= .40 (.931511)
They want me to know where they intersect. If you need more info, let me know

I'm a little confused. Is this a new problem or the same one? If it's a new one then you can make a new thread in a different section of the site, but if it's still about using your calculator then let's continue the discussion here :)

Either way can you post the complete problem?

 

[goosey00]

Re: stuck again

I'm a little confused. Is this a new problem or the same one? If it's a new one then you can make a new thread in a different section of the site, but if it's still about using your calculator then let's continue the discussion here :)

Either way can you post the complete problem?

Will you back in about an hour. ? I will right when i get back

 

[Jameson]

Re: stuck again

Will you back in about an hour. ? I will right when i get back

Ok, I'll be around and someone will surely help you today. I am on this site every day at different times and so are many others so you don't need to every worry about no one reading your questions.

 

[earboth]

On a scientific calculator, how do you get a root of a number for an exponiental? Ex.-.653846^1/12=
I was taking 1/12 and making it so I can make it exponent for .653846. Obviously wrong. What am I doing here??

1. Do you want to valuate

$$\displaystyle{\sqrt[12]{-.653846}}$$

You'll get an error message because an even root of a negative number has not a real value.

2. Do you want to valuate

(exp(-.653846))^(1/12)

Determine first $$\displaystyle{e^{-.653846} \approx 0.52}$$
and afterwards the 12^th root.