How to work out distance from a velocity-time graph when line is curved?

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SUMMARY

The discussion focuses on calculating the distance from a velocity-time graph with a curved line. The key method involves using definite integrals if the function is known, or approximating the area under the curve using numerical methods such as dividing the area into small triangular or trapezoidal sections. The user specifically sought assistance with sections B and C of the graph, and the solution emphasized the importance of integrating or approximating for accurate distance measurement. The conversation highlights practical techniques for handling curved graphs in physics problems.

PREREQUISITES
  • Understanding of velocity-time graphs
  • Knowledge of definite integrals
  • Familiarity with numerical approximation methods
  • Basic geometry for calculating areas of triangles and trapezoids
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  • Study the concept of definite integrals in calculus
  • Learn numerical integration techniques such as the trapezoidal rule
  • Explore the relationship between velocity, time, and distance in physics
  • Practice solving problems involving curved graphs and area calculations
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Students preparing for physics exams, educators teaching calculus and physics concepts, and anyone interested in understanding the practical applications of integration in real-world scenarios.

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Question from a mock exam I was looking over:

Homework Statement



I have a velocity-time graph and I understand the distance is the area underneath it, but the line is curved, so how can I calculate the area under it?
If possible show how you calculated distance under A,B,C,D (MOSTLY B AND C)
Thanks

Image: http://tinypic.com/r/2zohgd0/6

The Attempt at a Solution



The question in the exam was to find distance is section C and this is what I did (I had no clue, just guessed):

S=D/T
2=D/10
D=2*10
=20m travelled
 
Last edited:
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If you know the formula of the curve, then you can simply integrate (The area under the graph of a function, stretching between two points, A and B, is the definite integral of that function evaluated between A and B)

If you do not, then you can approximate it numerically. Cut the area into sufficiently small triangular or trapezoid pieces (You know how to calculate those areas), and the smaller your dicing is, the better an approximation will your calculation be to the actual area under the graph. (This is literally doing an integral by hand, without the formula for the function)
 
hmm ok thanks, I doubt we'll get formulas in the test, but I'll try the method of chopping down the curve
 

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