How would I graph this in my TI-83?

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To graph the equation |y| = 7 - x on a TI-83, one can either switch x and y to graph x on the vertical axis and y on the horizontal axis or use a parametric plot by letting yt = t and xt = 7 - |t|. This will create the desired V-shape, representing the absolute value function. Alternatively, graphing the lines y = 7 - x and y = x - 7 will also yield the correct intersecting lines. Testing points from each section can help determine which branches to include in the final graph.
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Homework Statement



|y| = 7-x

The closest I can do is y=abs(7-x), but this just gives me a straight line along the y axis. Thank you for your time.


Homework Equations





The Attempt at a Solution

 
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hyde2042 said:

Homework Statement



|y| = 7-x

The closest I can do is y=abs(7-x), but this just gives me a straight line along the y axis. Thank you for your time.
In this case x is a function of y, rather than y being a function of x.

You can either:
(1). Graph x on the vertical axis & y on the horizontal axis by switching x & y in your equation, then solve for y.

(2). Do a parametric plot: Let yt = t and xt = 7 - abs(t), because x = 7 - |y|. Have t go from -20 to 20.​
 
hyde2042 said:

Homework Statement



|y| = 7-x

The closest I can do is y=abs(7-x), but this just gives me a straight line along the y axis. Thank you for your time.


Homework Equations





The Attempt at a Solution


You could graph two lines: y = 7 - x and -y = 7 - x [better known as y = x - 7]

This would give to two intersecting lines making a large X

You only want two if the branches.

You want either the V, the inverted V [can't type it upside down] or the left hand two [>] or the right hand two [<].

You could test the original expression by chosing a known point on each of the sections, to check which two you want, if you can't think of any other way of doing it.
 
Ah. THank you guys. I wish I thought of those methods.
 
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