How would the arcsin function look like without a restricted range?

[tahayassen]

I need help. I'm totally puzzled. How would the arcsin function look like without a restricted range? Can anyone post an image?

http://img94.imageshack.us/img94/9886/arcsin.png

 

[dextercioby]

Why do you think the range is not R, but it is restricted ? Usually plotting computer software knows its maths...

 

[tahayassen]

Why do you think the range is not R, but it is restricted ? Usually plotting computer software knows its maths...

Hmm? I understand that arcsin is just the inverse of the sin function which is restricted between negative pi/2 and positive pi/2. But I want a graph of the function that is the inverse of the sin function without any domain restrictions on the sin function. It wouldn't be a function though, because it wouldn't pass the vertical line test.

 

[dextercioby]

So you want the subset of \mathbb{R}\oplus\mathbb{R} made up of

S= \{(x,\arcsin x)| x\in [-1,1]\}

and the values of arcsine are 'copied' from [-\pi/2,\pi/2] into [-\pi/2 +n\pi ,\pi/2 + n \pi] and n can take any integer value ?

So it's just an infinite multiplication of the plot of the standard arcsine with a shift along Oy axis of \pi.

 

[tahayassen]

So you want the subset of \mathbb{R}\oplus\mathbb{R} made up of

S= \{(x,\arcsin x)| x\in [-1,1]\}

and the values of arcsine are 'copied' from [-\pi/2,\pi/2] into [-\pi/2 +n\pi ,\pi/2 + n \pi] and n can take any integer value ?

So it's just an infinite multiplication of the plot of the standard arcsine with a shift along Oy axis of \pi.

I really wish I understood what a subset is. We're learning the inverse trigonometric functions in the trigonometry unit of my precalculus class, so I haven't really gotten into more complex stuff.

What do you mean by infinite multiplication of the plot of the standard arcsine? What's Oy and \pi?

 

[dextercioby]

Multiplication means repeating, copying the points in the plot of arcsin x, where x ranges from -1 to 1. Oy is the Y axis.

 

[tahayassen]

So it would look like this: http://img819.imageshack.us/img819/5679/62578051.png

 

[tahayassen]

Actually, no, that's wrong. I understand the arcsin's with vertical shifts of 2pi, but sin(x + pi) = -sin(x), so wouldn't the arcsin's with vertical shifts of npi (where n is every odd integer) need to be horizontally reflected?

 

[HallsofIvy]

Without restricting the domain, the graph of arcsine would look exactly like the graph of sine but along the y-axis, not the x-axis. Of course, that is not the graph of a function since one value of x would give infinitely many values of y.

 

[tahayassen]

Thanks everyone. It makes sense now.